4x^2=-25+25x

Solution for 4x^2=-25+25x equation:

4x^2=-25+25x

We move all terms to the left:

4x^2-(-25+25x)=0

We add all the numbers together, and all the variables

4x^2-(25x-25)=0

We get rid of parentheses

4x^2-25x+25=0

a = 4; b = -25; c = +25;
Δ = b2-4ac
Δ = -252-4·4·25
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-15}{2*4}=\frac{10}{8}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+15}{2*4}=\frac{40}{8}
=5
$